n^2+n-1=5

Solution for n^2+n-1=5 equation:

Simplifying
n2 + n + -1 = 5

Reorder the terms:
-1 + n + n2 = 5

Solving
-1 + n + n2 = 5

Solving for variable 'n'.

Reorder the terms:
-1 + -5 + n + n2 = 5 + -5

Combine like terms: -1 + -5 = -6
-6 + n + n2 = 5 + -5

Combine like terms: 5 + -5 = 0
-6 + n + n2 = 0

Factor a trinomial.
(-3 + -1n)(2 + -1n) = 0

Subproblem 1
Set the factor '(-3 + -1n)' equal to zero and attempt to solve:

Simplifying
-3 + -1n = 0

Solving
-3 + -1n = 0

Move all terms containing n to the left, all other terms to the right.

Add '3' to each side of the equation.
-3 + 3 + -1n = 0 + 3

Combine like terms: -3 + 3 = 0
0 + -1n = 0 + 3
-1n = 0 + 3

Combine like terms: 0 + 3 = 3
-1n = 3

Divide each side by '-1'.
n = -3

Simplifying
n = -3
Subproblem 2
Set the factor '(2 + -1n)' equal to zero and attempt to solve:

Simplifying
2 + -1n = 0

Solving
2 + -1n = 0

Move all terms containing n to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + -1n = 0 + -2

Combine like terms: 2 + -2 = 0
0 + -1n = 0 + -2
-1n = 0 + -2

Combine like terms: 0 + -2 = -2
-1n = -2

Divide each side by '-1'.
n = 2

Simplifying
n = 2
Solution
n = {-3, 2}